Interactive multiple-choice quiz: حل أنظمة المعادلات الخطية بالحذف
أوراق عمل شاملة تتضمن تدريبات متنوعة على حل أنظمة المعادلات الخطية باستخدام طريقة الحذف. تهدف هذه الأسئلة إلى تعزيز مهارات الطالب في التلاعب بالمعادلات جبرياً لإيجاد قيم المتغيرات بدقة. يغطي الاختبار حالات مختلفة تتطلب ضرب المعادلات في ثوابت لتوحيد المعاملات قبل إجراء الحذف.
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اختبار شهادة تدريبي مؤقت للصف والمادة والفصل نفسه.
اختر إجابة واحدة لكل سؤال. عند الاختيار ستظهر النتيجة فورًا: الأخضر صحيح، والأحمر خطأ، وسيظهر تفسير الإجابة مباشرة إن كان متوفرًا. وبعد آخر سؤال ستظهر الدرجة النهائية تلقائيًا.
Use elimination to solve the system of equations: 10x + 5y = 30 5x - 3y = -7
Explanation
Multiply the second equation by 2 to get 10x - 6y = -14. Subtracting this from the first equation gives 11y = 44, so y = 4. Substituting y = 4 into the first equation gives x = 1.
Use elimination to solve the system of equations: x + y = 2 -3x + 4y = 15
Explanation
Multiply the first equation by 3 to get 3x + 3y = 6. Adding this to the second equation gives 7y = 21, so y = 3. Substituting y = 3 into the first equation gives x = -1.
Use elimination to solve the system of equations: x - y = -8 7x + 5y = 16
Explanation
Multiply the first equation by 5 to get 5x - 5y = -40. Adding this to the second equation gives 12x = -24, so x = -2. Substituting x = -2 into the first equation gives y = 6.
Use elimination to solve the system of equations: x + 5y = 17 -4x + 3y = 24
Explanation
Multiply the first equation by 4 to get 4x + 20y = 68. Adding this to the second equation gives 23y = 92, so y = 4. Substituting y = 4 into the first equation gives x = -3.
Use elimination to solve the system of equations: 6x + y = -39 3x + 2y = -15
Explanation
Multiply the second equation by -2 to get -6x - 4y = 30. Adding this to the first equation gives -3y = -9, so y = 3. Substituting y = 3 into the second equation gives x = -7.
Use elimination to solve the system of equations: 2x + 5y = 11 4x + 3y = 1
Explanation
Multiply the first equation by -2 to get -4x - 10y = -22. Adding this to the second equation gives -7y = -21, so y = 3. Substituting y = 3 into the first equation gives x = -2.
Use elimination to solve the system of equations: 3x + 4y = 29 6x + 5y = 43
Explanation
Multiply the first equation by -2 to get -6x - 8y = -58. Adding this to the second equation gives -3y = -15, so y = 5. Substituting y = 5 into the first equation gives x = 3.
Use elimination to solve the system of equations: 8x + 3y = 4 -7x + 5y = -34
Explanation
Multiply the first by 5 and the second by -3 to align the y coefficients. Adding the resulting equations gives 61x = 122, so x = 2. Substituting x = 2 gives y = -4.
Use elimination to solve the system of equations: 8x + 3y = -7 7x + 2y = -3
Explanation
Multiply the first by 2 and the second by -3 to eliminate y. Adding gives -5x = -5, so x = 1. Substituting x = 1 into the second equation results in y = -5.
Use elimination to solve the system of equations: 12x - 3y = -3 6x + y = 1
Explanation
Multiply the second equation by 3 to get 18x + 3y = 3. Adding this to the first equation gives 30x = 0, so x = 0. Substituting x = 0 into the second equation gives y = 1.
Use elimination to solve the system of equations: 3x - 3y = -6 -5x + 6y = 12
Explanation
Multiply the first equation by 2 to get 6x - 6y = -12. Adding this to the second equation gives x = 0. Substituting x = 0 into the first equation gives -3y = -6, so y = 2.
Here are more quizzes for الصف التاسع العام by الفصل الثالث and subject رياضيات
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