Question 1
Points: 1
Find the value of x if Q is between P and R, PQ = 6x + 20, QR = 2(x + 6), and $\overline{PQ} \cong \overline{QR}$.
Explanation
Since the segments are congruent, their lengths are equal: 6x + 20 = 2(x + 6). Expanding gives 6x + 20 = 2x + 12. Subtracting 2x and 20 from both sides results in 4x = -8, so x = -2.







