Interactive multiple-choice quiz: اختبار الوحدة الثالثة (Similarity) ريفيل

A

enlargement; scale factor = $\frac{7}{4}$

B

reduction; scale factor = $\frac{4}{7}$

C

reduction; scale factor = $\frac{7}{4}$

D

enlargement; scale factor = $\frac{4}{7}$

A

$Z'(32, -8)$

B

$Z'(12, -16)$

C

$Z'(24, 20)$

D

$Z'(2, -0.5)$

A

k = 1.5

B

k = 0.67

C

k = 1.33

D

k = 2.0

A

Yes; the corresponding angles are congruent and the corresponding sides are proportional

B

No; the corresponding angles are not congruent

C

No; the corresponding angles are congruent, but the corresponding sides are not proportional

D

Yes; the scale factor is $\frac{7}{5}$

A

No. $\frac{MN}{GH} \neq \frac{NP}{HJ}$

B

Yes; the scale factor is 4

C

No; the corresponding angles are not congruent

D

Yes; the scale factor is 2.5

A

x = 64, y = 32

B

x = 63, y = 32

C

x = 64, y = 33

D

x = 98, y = 97

A

Yes; by the Triangle Angle-Sum Theorem, $m \angle A = 44^\circ$ and $m \angle G = 47^\circ$. Because two pairs of corresponding angles are congruent, $\triangle ABC$ is similar to $\triangle FGD$

B

Yes; by the Triangle Angle-Sum Theorem, $m \angle A = 46^\circ$ and $m \angle G = 46^\circ$. Because two pairs of corresponding angles are congruent, $\triangle ABC$ is similar to $\triangle DFG$

C

No; by the Triangle Angle-Sum Theorem, $m \angle A = 46^\circ$ and $m \angle G = 43^\circ$. Because no two pairs of angles are congruent, $\triangle ABC$ is not similar to $\triangle FGD$

D

No; by the Triangle Angle-Sum Theorem, $m \angle A = 44^\circ$ and $m \angle G = 43^\circ$. Because no two pairs of angles are congruent, $\triangle ABC$ is not similar to $\triangle DFG$

A

$\triangle DEF \sim \triangle GEH; EH = 14$

B

$\triangle EHG \sim \triangle EFD; EH = 9$

C

$\triangle DEF \sim \triangle GEH; EH = 9$

D

$\triangle EHG \sim \triangle EFD; EH = 15$

A

Yes; the corresponding sides are proportional using SSS Similarity Postulate

B

No; the corresponding sides are not proportional

C

Yes; the corresponding angles are congruent using AA Similarity Postulate

D

No; the corresponding angles are not congruent

A

$\triangle TWZ \sim \triangle YWX$ by SSS Similarity, because $\frac{TW}{YW} = \frac{WZ}{WX} = \frac{TZ}{YX} = \frac{1}{2}$

B

$\triangle TWZ$ is not similar to $\triangle YWX$ because the corresponding angles at vertex W are not congruent

C

$\triangle TWZ \sim \triangle YWX$ by SAS Similarity, because $\angle TWZ \cong \angle YWX$ and $\frac{TW}{YW} = \frac{WZ}{WX} = \frac{1}{2}$

D

$\triangle TWZ$ is not similar to $\triangle YWX$ because the corresponding sides are not proportional ($\frac{TW}{YW} \neq \frac{WZ}{WX}$)

A

RT = 8

B

RT = 10

C

RT = 12

D

RT = 14

A

12.2 miles

B

8.1 miles

C

12.3 miles

D

15.5 miles

A

AB = 19.5

B

AB = 28

C

AB = 32.5

D

AB = 39

A

ED = 4.5

B

ED = 10

C

ED = 13.5

D

ED = 6

A

x = 12.5

B

x = 25

C

x = 75

D

x = 50

A

x = 6, y = 13

B

x = 6, y = 6.5

C

x = 8, y = 6.5

D

x = 8, y = 13

A

x = 7

B

x = 8

C

x = 10.5

D

x = 14

A

x = 13.86

B

x = 15.12

C

x = 18.90

D

x = 17.14

A

MN = 14

B

MN = 20

C

MN = 32

D

MN = 18

A

EY = 5.3 cm

B

EY = 6.5 cm

C

EY = 7.2 cm

D

EY = 12.0 cm