اختبار اختيار من متعدد تفاعلي: مراجعة المساحات والحجوم الدورانية

أ

$A = \int_0^2 (2 - 2x) dx$

ب

$A = \int_0^1 (2 - y) dy$

ج

$A = \int_0^1 (2 - 2y) dy$

د

$A = \int_0^2 (y - 2) dy$

أ

$A = \int_0^2 (2 - 2x) dx$

ب

$A = \int_0^1 (2 - y) dy$

ج

$A = \int_0^1 (2 - 2y) dy$

د

$A = \int_0^2 (6 - 2y) dy$

أ

$A = \int_0^1 (y) dy$

ب

$A = \int_0^1 (2y) dy$

ج

$A = \int_0^1 (2x) dx$

د

$A = \int_0^1 (x) dx$

أ

$A = \int_0^1 (2 - x - x^2) dx$

ب

$A = \int_1^2 (3y - 2 - y^2) dy$

ج

$A = \int_1^2 (3y - 2 + y^2) dy$

د

$A = \int_0^2 (2 - y) dy$

أ

$A = \int_0^1 (3 - x^2 - 2x) dx$

ب

$A = \int_0^1 (3 - 2y - y^2) dy$

ج

$A = \int_0^1 (3 + x^2 + 2x) dx$

د

$A = \int_0^1 (3 - x^2 + 2x) dx$

أ

$A = \int_0^3 (4 - \sqrt{x}) dx$

ب

$A = \int_{-2}^2 (4 - y^2) dy$

ج

$A = \int_{-2}^2 (y^2 - 4) dy$

د

$A = \int_{-2}^2 (y^2 + 4) dy$

أ

$v = \int_0^4 (4 - 2x)^2 dx$

ب

$v = \int_0^2 \pi (4 - 2x)^2 dx$

ج

$v = \int_0^x \pi (4 - 2x)^2 dx$

د

$v = \int_0^2 (4 - 2x)^2 dx$

أ

$v = \int_0^4 (8 - 2x)^2 dx$

ب

$v = \pi \int_0^2 [(8 - 2x)^2 - 4^2] dx$

ج

$v = \pi \int_0^2 [4^2 - (2x)^2] dx$

د

$v = \int_0^2 (8 - 2y)^2 dy$

أ

$v = \int_0^4 (8 - 2x)^2 dx$

ب

$v = \pi \int_0^2 [(8 - 2x)^2 - 4^2] dx$

ج

$v = \pi \int_0^2 [4^2 - (2x)^2] dx$

د

$v = \int_0^2 (8 - 2y)^2 dy$

أ

$v = \int_0^4 \pi [(2 + \sqrt{y})^2 - (2 - \sqrt{y})^2] dy$

ب

$v = \pi \int_0^4 (\sqrt{y})^2 dy$

ج

$v = \int_0^4 \pi [(2 - \sqrt{y})^2 - (2 + \sqrt{y})^2] dy$

د

$v = \int_0^4 \pi [(4 + \sqrt{y})^2 - (4 - \sqrt{y})^2] dy$