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كويز تفاعلي: Centripetal Force Physics Assessment - inspire
Centripetal force is the inward force required to maintain an object's circular motion, acting perpendicular to its velocity and directed toward the center of the path. Its magnitude is determined by the object's mass, its speed, and the radius of the circular path according to the physical law \( F_c = \frac{mv^2}{r} \). This assessment explores these relationships through conceptual questions and practical calculations, such as determining the force on a rotating ball or calculating the required radius for a road turn based on safety acceleration limits. Understanding these principles is essential for engineering, aeronautics, and basic physics mechanics.
رقم الاختبار798
الصفالصف الثاني عشر المتقدم
المادةفيزياء
الفصلالفصل الثالث
السنة الدراسية2025/2026
عدد الأسئلة7
إجمالي النقاط7
تاريخ الإضافة2026-04-19
الزيارات201
الناشرAmal Salman
يرجى الانتباه إلى أن المعلم قام بإعداد الأسئلة فقط، ولم يقم بإعداد الإجابات أو الشروحات المرفقة. وقد تم توليد الإجابات باستخدام تقنيات الذكاء الاصطناعي، لذلك قد تتضمن بعض الأخطاء أو عدم الدقة.
للحصول على الإجابات الصحيحة والمضمونة، يُرجى الرجوع إلى المعلم أو المصدر الدراسي المعتمد.
Question 1
Points: 1
A horse gallops around a circular arena. The centripetal force on the horse is ___.
According to the formula \( F_c = \frac{m v^2}{r} \), the centripetal force is directly proportional to the square of the velocity; therefore, increasing velocity increases the force.
Question 3
Points: 1
Calculate the amount of centripetal force it takes for a softball pitcher to rotate a ball with a velocity of 3 m/s if the ball weighs .12 kg and her arm is .65 meters long.
Using the formula \( F_c = \frac{m v^2}{r} \), where m = 0.12, v = 3, and r = 0.65. Calculation: \( \frac{0.12 \times 3^2}{0.65} = \frac{0.12 \times 9}{0.65} = \frac{1.08}{0.65} \approx 1.66 \text{ N} \).
Question 4
Points: 1
A bola is an old hunting instrument. If three rocks with a combined mass of 0.75 kg are spun at a speed of 20 m/s with a radius of 0.5 m, how much centripetal force is required to keep them spinning.
Using the centripetal force formula \( F_c = \frac{m v^2}{r} \): \( F_c = \frac{0.75 \times 20^2}{0.5} = \frac{0.75 \times 400}{0.5} = \frac{300}{0.5} = 600 \text{ N} \).
Question 5
Points: 1
An engineer is planning a road with a turn. If the speed limit is 20 m/s and the centripetal acceleration cannot exceed 8.5 m/s/s, how big must the radius of the turn be?
Centripetal acceleration is defined as \( a_c = \frac{v^2}{r} \). Rearranging for radius: \( r = \frac{v^2}{a_c} = \frac{20^2}{8.5} = \frac{400}{8.5} \approx 47.05 \text{ m} \). The closest option is 47 m.
Question 6
Points: 1
A car with mass m travels around a curve with velocity v. What do you know about the centripetal force if the velocity triples?
Centripetal force is proportional to the square of the velocity (\( F_c \propto v^2 \)). If velocity is multiplied by 3, the force is multiplied by 32 = 9.
Question 7
Points: 1
A car with mass m travels around a curve with velocity v. What do you know about the centripetal force if the radius triples?
Centripetal force is inversely proportional to the radius (\( F_c \propto \frac{1}{r} \)). If the radius is tripled, the force is reduced to one-third of its original value.
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