كويز تفاعلي: 20 سؤال: الأسئلة الموضوعية لهيكل الرياضيات 12 متقدم - الفصل الثالث 2025-2026

أ

$-\frac{2}{7}(\cos x + 3)^{\frac{7}{2}} + c$

ب

$\frac{4}{7}(\cos x + 3)^{\frac{7}{4}} + c$

ج

$-\frac{4}{7}(\cos x + 3)^{\frac{7}{4}} + c$

د

$-\frac{7}{4}(\cos x + 3)^{\frac{7}{4}} + c$

أ

$\frac{1}{2} e^{x^2+1} + c$

ب

$\frac{1}{2} x e^{x^2+1} + c$

ج

$\frac{3}{2} e^{x^2+1} + c$

د

2 e^x2+1 + c

أ

$\frac{1}{2}(e^x + 1)^{\frac{3}{2}} + c$

ب

$\frac{2}{3}(e^x + 1)^{\frac{3}{2}} + c$

ج

$\frac{3}{2}(e^x + 1)^{\frac{3}{2}} + c$

د

$\frac{2}{3}(e^x + 1)^{\frac{2}{3}} + c$

أ

$\frac{1}{2 e^{\sqrt{x}}} + c$

ب

$\frac{1}{2} e^{\sqrt{x}} + c$

ج

$\frac{2}{e^{\sqrt{x}}} + c$

د

$2 e^{\sqrt{x}} + c$

أ

$-\sin \frac{1}{x^2} + c$

ب

$-\sin \frac{1}{x} + c$

ج

$\sin \frac{1}{x} + c$

د

$\sin \frac{1}{x^2} + c$

أ

$-\frac{\sin^6 x}{6} + c$

ب

$\frac{\sin^6 x}{6} + c$

ج

$-\frac{\cos^6 x}{6} + c$

د

6 sin⁵ x cos x + c

أ

$-2 \sin \sqrt{x} + c$

ب

$-2 \cos \sqrt{x} + c$

ج

$2 \sin \sqrt{x} + c$

د

$2 \cos \sqrt{x} + c$

أ

$\ln |\frac{x^5}{1 + x^6}| + c$

ب

$\frac{1}{5} \ln |1 + x^5| + c$

ج

$\ln |1 + x^6|^{\frac{1}{6}} + c$

د

$\frac{1}{6} x^6 \ln |x| + c$

أ

tan^-1 x³ + c

ب

$\tan^{-1} \frac{x^3}{3} + c$

ج

$\frac{1}{3} \tan^{-1} x^3 + c$

د

tan^-1 x + c

أ

$\tan^{-1} x^{\frac{3}{2}} + c$

ب

$\frac{1}{2} \tan^{-1} x^{\frac{2}{3}} + c$

ج

$\frac{1}{2} \tan^{-1} x^{\frac{3}{2}} + c$

د

$2 \tan^{-1} x^{\frac{3}{2}} + c$

أ

$\frac{2}{5} \tan^{-1} x^{\frac{5}{2}} + c$

ب

$\frac{5}{2} \tan^{-1} x^{\frac{5}{2}} + c$

ج

$\frac{1}{5} \tan^{-1} x^{\frac{5}{2}} + c$

د

$\frac{1}{2} \tan^{-1} x^{\frac{5}{2}} + c$

أ

$\tan^{-1} e^2 - \frac{\pi}{2}$

ب

$\frac{\pi}{4} \tan^{-1} e^2$

ج

$\frac{1}{5} \tan^{-1} e^2 - \frac{\pi}{4}$

د

$\tan^{-1} e^2 - \frac{\pi}{4}$

أ

$\ln |9x^2 + 9x + 1| + c$

ب

$2 \ln |9x^2 + 9x + 1| + c$

ج

$2 \ln |36x + 18| + c$

د

2 (9x² + 9x + 1) + c

أ

$A = \frac{1}{3}$

ب

$A = \frac{64}{3}$

ج

$A = \frac{4\sqrt{2}}{3}$

د

$A = \frac{27}{4}$

أ

$A = \frac{1}{3}$

ب

$A = \frac{64}{3}$

ج

$A = \frac{4\sqrt{2}}{3}$

د

$A = \frac{27}{4}$

أ

$A = \frac{1}{3}$

ب

$A = \frac{64}{3}$

ج

$A = \frac{4\sqrt{2}}{3}$

د

$A = \frac{27}{4}$

أ

$A = \frac{1}{3}$

ب

$A = \frac{64}{3}$

ج

$A = \frac{4\sqrt{2}}{3}$

د

$A = \frac{27}{4}$

أ

$A = \int_0^1 (2 - 2x^2) dx + \int_1^2 (2x^2 - 2) dx$

ب

$A = \int_0^1 (2x^2 - 1) dx + \int_1^2 (2 - 2x^2) dx$

ج

$A = \int_0^1 x^2 dx + \int_1^2 (2x^2 - 2) dx$

د

$A = \int_0^2 (2 - 2x^2) dx$

أ

$A = \int_{-1}^1 (x - x^2) dx$

ب

$A = \int_0^1 (x^2 - x) dx$

ج

$A = \int_0^1 (x - x^2) dx$

د

$A = \int_{-1}^1 (x^2 - x) dx$

أ

$A = \int_1^4 (5y - (4 + y^2)) dy$

ب

$A = \int_5^{20} ((4 + y^2) - 5y) dy$

ج

$A = \int_5^{20} (5x - (4 + x^2)) dx$

د

$A = \int_1^4 ((4 + x^2) - 5x) dx$