كويز تفاعلي: Quadratic Formula & The Discriminant - Reveal

A

ax² + bx + c

B

b - 4ac

C

b² - 4ac

D

b² + 4ac

A

101; 2 real roots

B

3; 2 real roots

C

-101; 2 imaginary roots

D

-3; 2 imaginary roots

A

x = -2, 3

B

x = 2, 3

C

x = 2, -3

D

x = -2, -3

A

1 Real Solution

B

2 Real Solutions

C

Half a Solution

D

2 Complex (imaginary) Solutions

A

True

B

False

A

\(\frac{3 \pm \sqrt{33}}{4}\)

B

\(\frac{-1 \pm \sqrt{13}}{2}\)

C

\{2, 1\}

D

\(\frac{3 \pm \sqrt{17}}{2}\)

A

\(x = \frac{2 \pm 2i\sqrt{10}}{2}\)

B

\(x = \frac{4 \pm \sqrt{40}}{4}\)

C

\(x = \frac{2 \pm i\sqrt{10}}{2}\)

D

\(x = \frac{2 \pm 2i\sqrt{40}}{4}\)

A

No solutions

B

\(x = 1\ \text{solution}\)

C

\(x = 2\ \text{solutions}\)

D

\(x = \infty\ \text{solutions}\)

A

No solutions

B

\(1\ \text{solution}\)

C

\(2\ \text{solutions}\)

D

\(\infty\ \text{solutions}\)

A

\(x = \frac{-1 \pm \sqrt{10}}{3}\)

B

\(x = 2,\ -1\)

C

\(x = 2,\ -3\)

D

\(x = 1,\ -2\)

A

\(x = \frac{7}{2},\x = -6\)

B

\(x = -\frac{5}{2},\x = 5\)

C

\(x = -\frac{3}{7},\x = 6\)

D

\(x = -\frac{5}{2},\x = 7\)

A

\(x = \frac{5 - i\sqrt{15}}{2},\ \frac{5 + i\sqrt{15}}{2}\)

B

\(x = \frac{5 - \sqrt{15}}{2},\ \frac{5 + \sqrt{15}}{2}\)

C

\(x = \frac{5 - i\sqrt{65}}{2},\ \frac{5 + i\sqrt{65}}{2}\)

D

\(x = \frac{5 - \sqrt{65}}{2},\ \frac{5 + \sqrt{65}}{2}\)

A

\(x = 1 \pm i\)

B

\(x = 3,\ -6\)

C

\(x = 4.8,\ 2.7\)

D

Undefined

A

\(x = -\frac{9}{2},\ 4\)

B

\(x = \frac{9}{2},\ -4\)

C

\(x = 4,\ -4\)

D

No real solution

A

Because zero is an easy number to work with.

B

Because we are trying to find the x-intercepts and that happens when y = 0.

C

Because setting it equal to zero helps us find the y-intercepts.

D

None of the above